1. Fundamental Concepts
- Definition: Work is the energy transferred to or from an object via a force acting on the object in the direction of its displacement.
- Formula: The work \(W\) done by a constant force \(F\) along a displacement \(d\) is given by \(W = F \cdot d\).
- Units: The standard unit of work is the joule (J), where \(1 \text{ J} = 1 \text{ N} \cdot 1 \text{ m}\).
2. Key Concepts
Basic Rule: $$W = F \cdot d$$
Directional Component: When the force and displacement are not in the same direction, use the component of force in the direction of displacement: \(W = F \cdot d \cdot \cos(\theta)\).
Application: Used to calculate energy transfer in physics problems involving motion and forces.
3. Examples
Example 1 (Basic)
Problem: Calculate the work done by a force of \(5 \text{ N}\) that moves an object \(10 \text{ m}\) in the same direction.
Step-by-Step Solution:
- Identify the force \(F = 5 \text{ N}\) and the displacement \(d = 10 \text{ m}\).
- Apply the formula: \(W = F \cdot d = 5 \cdot 10 = 50 \text{ J}\).
Validation: Substitute values into the formula → Original: \(5 \cdot 10 = 50\); Simplified: \(50 \text{ J}\) ✓
Example 2 (Intermediate)
Problem: A force of \(10 \text{ N}\) acts at an angle of \(60^\circ\) to the direction of displacement of \(5 \text{ m}\). Calculate the work done.
Step-by-Step Solution:
- Identify the force \(F = 10 \text{ N}\), the displacement \(d = 5 \text{ m}\), and the angle \(\theta = 60^\circ\).
- Calculate the component of force in the direction of displacement: \(F \cdot \cos(60^\circ) = 10 \cdot \frac{1}{2} = 5 \text{ N}\).
- Apply the formula: \(W = F \cdot d \cdot \cos(\theta) = 5 \cdot 5 = 25 \text{ J}\).
Validation: Substitute values into the formula → Original: \(10 \cdot 5 \cdot \cos(60^\circ) = 25\); Simplified: \(25 \text{ J}\) ✓
4. Problem-Solving Techniques
- Visual Strategy: Draw diagrams to represent forces and displacements.
- Error-Proofing: Always check the units and ensure they are consistent throughout the calculation.
- Concept Reinforcement: Understand the physical meaning of each term in the work formula.