Diffusion

Biology

1. Fundamental Concepts

  • Definition: Diffusion is the net movement of molecules from an area of high concentration to an area of low concentration until equilibrium is reached.
  • Concentration Gradient: The difference in concentration that drives diffusion.
  • Passive Transport: Movement of substances across a cell membrane without the use of energy.

2. Key Concepts

Fick's First Law of Diffusion: $J = -D \cdot \frac{\partial C}{\partial x}$

Where \( J \) is the flux, \( D \) is the diffusion coefficient, and \( \frac{\partial C}{\partial x} \) is the concentration gradient.

Factors Affecting Diffusion:
  • Temperature: Higher temperatures increase molecular motion.
  • Molecular Size: Smaller molecules diffuse faster.
  • Distance: Greater distances require more time for diffusion.
Application: Diffusion plays a crucial role in cellular processes such as nutrient uptake and waste removal.

3. Examples

Example 1 (Basic)

Problem: Consider two chambers separated by a permeable membrane. Chamber A has a concentration of glucose (\( C_A = 0.5 \text{ M} \)) and Chamber B has a concentration of \( C_B = 0.1 \text{ M} \). If the diffusion coefficient (\( D \)) is \( 1 \times 10^{-9} \text{ m}^2/\text{s} \) and the distance between the chambers is \( 0.001 \text{ m} \), calculate the flux (\( J \)).

Step-by-Step Solution:

  1. Calculate the concentration gradient: \( \frac{\partial C}{\partial x} = \frac{C_A - C_B}{x} = \frac{0.5 - 0.1}{0.001} = 400 \text{ M/m} \).
  2. Apply Fick's First Law: \( J = -D \cdot \frac{\partial C}{\partial x} = -(1 \times 10^{-9}) \cdot 400 = -4 \times 10^{-7} \text{ M/s} \).
Validation: The negative value indicates the direction of diffusion from high to low concentration.

Example 2 (Intermediate)

Problem: In a biological system, the concentration of oxygen in blood is \( C_1 = 0.2 \text{ M} \) and in tissue is \( C_2 = 0.05 \text{ M} \). Given the diffusion coefficient \( D = 2 \times 10^{-10} \text{ m}^2/\text{s} \) and the thickness of the tissue layer \( x = 0.002 \text{ m} \), find the rate of oxygen diffusion.

Step-by-Step Solution:

  1. Calculate the concentration gradient: \( \frac{\partial C}{\partial x} = \frac{C_1 - C_2}{x} = \frac{0.2 - 0.05}{0.002} = 75 \text{ M/m} \).
  2. Apply Fick's First Law: \( J = -D \cdot \frac{\partial C}{\partial x} = -(2 \times 10^{-10}) \cdot 75 = -1.5 \times 10^{-8} \text{ M/s} \).
Validation: The calculated flux matches the expected direction and magnitude for oxygen diffusion in biological systems.

4. Problem-Solving Techniques

  • Visual Strategy: Use diagrams to represent concentration gradients and diffusion paths.
  • Error-Proofing: Double-check units and ensure consistent use of SI units throughout calculations.
  • Concept Reinforcement: Relate theoretical concepts to real-world examples, such as gas exchange in lungs or nutrient absorption in cells.