Electronegativity

Chemistry

1. Fundamental Concepts

  • Definition: The relative ability of an atom in a chemical compound to attract shared electrons to itself (dimensionless, relative value).
  • Core Idea: Higher electronegativity means stronger electron-attracting ability, making the atom more likely to form a negative oxidation state.
  • Reference Scale: Pauling scale (the most commonly used), where fluorine (F) has the highest electronegativity (3.98) and cesium (Cs) has the lowest (0.79).

2. Key Concepts

  1. Periodic Trends
    • Across a period (left to right): Electronegativity increases (due to increasing nuclear charge and decreasing atomic radius).
    • Down a group (top to bottom): Electronegativity decreases (due to increasing atomic radius outweighing the effect of increased nuclear charge).
  2. Bond Type Correlation
    • Electronegativity difference (ΔEN) > 1.7: Ionic bond (e.g., NaCl: Na 0.93, Cl 3.16, ΔEN = 2.23).
    • Electronegativity difference (ΔEN) < 1.7: Covalent bond
      • ΔEN = 0–0.4: Nonpolar covalent bond (e.g., O₂).
      • ΔEN = 0.4–1.7: Polar covalent bond (e.g., HCl).
  3. Characteristics
    • No absolute numerical value, only for relative comparison.
    • Metals generally have electronegativity < 1.8; nonmetals generally have electronegativity > 1.8.

3. Examples

Easy

Question: Determine the bond type between hydrogen (H, 2.20) and oxygen (O, 3.44).
Analysis: Calculate the electronegativity difference: ΔEN = 3.44 - 2.20 = 1.24. Since 1.24 < 1.7, the bond is a polar covalent bond.

Medium

Question: Compare the electronegativity of carbon (C, 2.55), nitrogen (N, 3.04), and silicon (Si, 1.90), and arrange them in descending order.
Analysis: Apply periodic trends:
  • C and N are in the same period; N is to the right of C, so EN(N) > EN(C).
  • C and Si are in the same group; C is above Si, so EN(C) > EN(Si).
     
    ConclusionN > C > Si

Hard

Question: Explain why AlCl₃ (Al 1.61, Cl 3.16) is a covalent compound while NaCl (Na 0.93, Cl 3.16) is an ionic compound.Analysis:
  1. Calculate electronegativity differences:
    • Al-Cl: ΔEN = 3.16 - 1.61 = 1.55 (< 1.7)
    • Na-Cl: ΔEN = 3.16 - 0.93 = 2.23 (> 1.7)
  2. Consider ionic polarization: Al³⁺ has a small radius and high charge, leading to strong polarizing power. It distorts the electron cloud of Cl⁻, making the bond transition from ionic to covalent. Na⁺ has a larger radius and lower charge, with weak polarizing power, forming a typical ionic bond.
     
    Conclusion: AlCl₃ is covalent due to small ΔEN and strong ionic polarization; NaCl is ionic due to large ΔEN and weak ionic polarization.

4. Problem-Solving Techniques

  • Trend Application
    • Prioritize using "increase across a period, decrease down a group" to judge relative electronegativity, avoiding the trap of absolute numerical values.
  • Bond Type Judgment
    • Use 1.7 as the critical value for ΔEN. Assist the judgment with ionic polarization (cations with high charge and small radius have strong polarizing power, leading to covalent bond tendency).
  • Oxidation State Inference
    • Atoms with higher electronegativity exhibit negative oxidation states; those with lower electronegativity exhibit positive oxidation states (e.g., O is negative and H is positive in H₂O).