1. Fundamental Concepts
- Definition: The 'h' value in an exponential function of the form $$f(x) = a \cdot b^{(x-h)} + k$$ represents the horizontal shift of the graph.
- Horizontal Shift: If 'h' is positive, the graph shifts right by 'h' units; if 'h' is negative, the graph shifts left by 'h' units.
- Graphical Interpretation: The value of 'h' affects where the vertex of the exponential function's graph lies on the x-axis.
2. Key Concepts
Basic Rule: $$f(x) = a \cdot b^{(x-h)} + k$$
Shift Direction: Positive 'h' shifts the graph to the right; negative 'h' shifts the graph to the left.
Application: Used in modeling real-world phenomena such as population growth and radioactive decay.
3. Examples
Example 1 (Basic)
Problem: Identify the horizontal shift for the function $$f(x) = 2 \cdot 3^{(x-4)} + 1$$
Step-by-Step Solution:
- The function is in the form $$f(x) = a \cdot b^{(x-h)} + k$$ with $$a = 2$$, $$b = 3$$, $$h = 4$$, and $$k = 1$$.
- Since 'h' is positive, the graph shifts right by 4 units.
Validation: Substitute x=0 → Original: 2 \cdot 3^{-4} + 1; Simplified: 2 \cdot \frac{1}{81} + 1 ≈ 1.0247 ✓
Example 2 (Intermediate)
Problem: Write the equation of an exponential function that has been shifted 3 units to the left and has a vertical stretch factor of 5.
Step-by-Step Solution:
- Start with the base function $$f(x) = b^x$$.
- Apply the vertical stretch factor: $$f(x) = 5 \cdot b^x$$.
- Apply the horizontal shift: $$f(x) = 5 \cdot b^{(x+3)}$$.
Validation: Substitute x=-3 → Original: 5 \cdot b^0 = 5; Simplified: 5 ✓
4. Problem-Solving Techniques
- Visual Strategy: Graph the function before and after applying the shift to visualize the change.
- Error-Proofing: Always check the sign of 'h' to determine the direction of the shift.
- Concept Reinforcement: Practice with various values of 'h' to understand its impact on the graph.