Graphing Quadratic Functions in Vertex Form Using Transformations
Algebra-2
1. Fundamental Concepts
Parabola: The graph of a quadratic function, which is a U-shaped curve.
Vertex: The key point of a parabola, which is the minimum or maximum point.
Axis of Symmetry: A vertical line that passes through the vertex, dividing the parabola into two symmetrical halves.
Vertex Form of a Quadratic Function: The form is $f(x)=a(x-h)^2 + k$ , where $(h,k)$ is the vertex of the parabola.
2. Key Concepts
Role of a:
Responsible for vertical compression or stretch of the parabola. If $|a|>1$ , the parabola is stretched vertically; if $0<|a|<1$ , it is compressed vertically.
The sign of a determines the direction the parabola opens. If $a>0$ , the parabola opens upward; if $a<0$ , it opens downward.
Role of h: Causes horizontal translation of the parent function $f(x)=x^2$ . If $h>0$ , the graph shifts h units to the right; if $h<0$ , the graph shifts $|h|$ units to the left.
Role of k: Causes vertical translation of the parent function $f(x)=x^2$ . If $k>0$ , the graph shifts k units upward; if $k<0$ , the graph shifts $|k|$ units downward.
Transformation Rules: When graphing a quadratic function in vertex form, we start with the parent function $f(x)=x^2$ (which has a vertex at $(0,0)$ and opens upward) and apply the transformations based on the values of a, h, and k in the vertex form $f(x)=a(x-h)^2 + k$ .
3. Examples
Simple: Graph $f(x)=(x-3)^2 + 4$
Start with the parent function $f(x)=x^2$ with vertex $(0,0)$ .
Since $h = 3$ , shift the graph 3 units to the right.
Since $k=4$ , shift the resulting graph 4 units upward.
The vertex of the new parabola is $(3,4)$ , and it opens upward (since $a = 1>0$ ) with the same width as the parent function.
Medium: Graph $f(x)=2(x + 3)^2$
Begin with $f(x)=x^2$ (vertex $(0,0)$ ).
Because $h=-3$ , shift the graph 3 units to the left.
Due to $a = 2>0$ , stretch the graph vertically by a factor of 2.
The vertex is $(-3,0)$ , and the parabola opens upward, being narrower than the parent function.
Difficult: Graph $f(x)=-3(x + 1)^2-2$
Start with $f(x)=x^2$ (vertex $(0,0)$ ).
Since $h=-1$ , shift the graph 1 unit to the left.
Because $a=-3<0$ , reflect the graph over the x-axis and stretch it vertically by a factor of 3.
Due to $k=-2$ , shift the resulting graph 2 units downward.
The vertex is $(-1,-2)$ , and the parabola opens downward, being narrower than the parent function.
4. Problem-Solving Techniques
Identify the Vertex: From the vertex form $f(x)=a(x-h)^2 + k$ , directly obtain the vertex $(h,k)$ .
Determine the Direction of Opening: Check the sign of a to know if the parabola opens upward ( $a>0$ ) or downward ( $a<0$ ).
Apply Transformations Step by Step: Start with the parent function $f(x)=x^2$ and apply horizontal translation (based on h), vertical stretch/compression and reflection (based on a), and vertical translation (based on k) in sequence.
Plot Key Points: After determining the vertex, use the symmetry of the parabola (with respect to the axis of symmetry $x = h$ ) to plot additional points. For example, if one point $(x,y)$ is on the parabola, then the point $(2h-x,y)$ (symmetrical to $(x,y)$ about the axis of symmetry) is also on the parabola.
Sketch the Parabola: Connect the plotted points smoothly to form the parabola.