1. Fundamental Concepts
- Definition: The Hardy-Weinberg equilibrium is a principle that states the allele and genotype frequencies in a population will remain constant from generation to generation in the absence of other evolutionary influences.
- Assumption: One of the key assumptions for the Hardy-Weinberg equilibrium to hold is that the population must be large.
- Implication: In a large population, random mating and genetic drift have minimal effects on allele frequencies.
2. Key Concepts
Population Size: $p^2 + 2pq + q^2 = 1$
Gene Frequency: $p + q = 1$
Application: Used to predict the frequency of alleles and genotypes in a population
3. Examples
Example 1 (Basic)
Problem: Suppose in a large population, the frequency of the dominant allele \(A\) is \(0.7\). What is the frequency of the recessive allele \(a\)?
Step-by-Step Solution:
- Given \(p = 0.7\), where \(p\) is the frequency of the dominant allele \(A\).
- Using the equation \(p + q = 1\), solve for \(q\): \(0.7 + q = 1 \Rightarrow q = 0.3\).
Validation: Substitute \(p = 0.7\) and \(q = 0.3\) into \(p + q = 1\): \(0.7 + 0.3 = 1\) ✓
Example 2 (Intermediate)
Problem: If the frequency of homozygous recessive individuals (\(aa\)) in a population is \(0.09\), what are the frequencies of the alleles \(A\) and \(a\)?
Step-by-Step Solution:
- The frequency of homozygous recessive individuals is given by \(q^2 = 0.09\).
- Solve for \(q\): \(q = \sqrt{0.09} = 0.3\).
- Using \(p + q = 1\), solve for \(p\): \(p = 1 - 0.3 = 0.7\).
Validation: Substitute \(q = 0.3\) into \(q^2 = 0.09\): \(0.3^2 = 0.09\) ✓
4. Problem-Solving Techniques
- Visual Strategy: Use pie charts to represent allele frequencies visually.
- Error-Proofing: Always check if the sum of allele frequencies equals 1.
- Concept Reinforcement: Practice with different scenarios to understand the impact of population size on genetic variation.