1. Fundamental Concepts
- Definition: The process of eliminating radicals (e.g., \(\sqrt{2}\), \(\sqrt[3]{5}\)) from the denominator of a fractional expression, as radicals in the denominator are not in "simplest form."
- Rationalizing Factor: A radical (or expression) multiplied by the numerator and denominator to remove the radical from the denominator (e.g., \(\sqrt[3]{4}\) is the factor for \(\sqrt[3]{2}\)).
- Prerequisite: For even indices (2, 4...), radicands ≥ 0; for odd indices (3, 5...), radicands ≠ 0 (avoid division by zero).
2. Key Concepts
- Core Goal: Make the denominator a rational number while keeping the expression’s value unchanged (multiply numerator and denominator by the same factor).
- Two Main Scenarios:
- Single radical in denominator: Multiply by \(\sqrt[n]{k^{n-1}}\) (where n = index, k = radicand) to get \(\sqrt[n]{k^n}=k\) (rational).
- Binomial radical in denominator: Multiply by the conjugate (flip the sign between terms, e.g., \(\sqrt{a}-\sqrt{b}\) for \(\sqrt{a}+\sqrt{b}\)) to use \((a+b)(a-b)=a^2-b^2\) (rational).
3. Examples
(1) Easy
Question: Rationalize \(\frac{3}{\sqrt{5}}\)
Solution: Multiply by \(\sqrt{5}\): \(\frac{3\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{3\sqrt{5}}{5}\)
Answer: \(\frac{3\sqrt{5}}{5}\)
Solution: Multiply by \(\sqrt{5}\): \(\frac{3\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{3\sqrt{5}}{5}\)
Answer: \(\frac{3\sqrt{5}}{5}\)
(2) Medium
Question: Rationalize \(\frac{2}{\sqrt[3]{4x}}\) (\(x≠0\))
Solution: Multiply by \(\sqrt[3]{2x^2}\): \(\frac{2\sqrt[3]{2x^2}}{\sqrt[3]{4x\times2x^2}}=\frac{2\sqrt[3]{2x^2}}{\sqrt[3]{8x^3}}=\frac{2\sqrt[3]{2x^2}}{2x}=\frac{\sqrt[3]{2x^2}}{x}\)
Answer: \(\frac{\sqrt[3]{2x^2}}{x}\)
Solution: Multiply by \(\sqrt[3]{2x^2}\): \(\frac{2\sqrt[3]{2x^2}}{\sqrt[3]{4x\times2x^2}}=\frac{2\sqrt[3]{2x^2}}{\sqrt[3]{8x^3}}=\frac{2\sqrt[3]{2x^2}}{2x}=\frac{\sqrt[3]{2x^2}}{x}\)
Answer: \(\frac{\sqrt[3]{2x^2}}{x}\)
(3) Hard
Question: Rationalize \(\frac{4}{\sqrt{3}+\sqrt{2}}\)
Solution: Multiply by \(\sqrt{3}-\sqrt{2}\): \(\frac{4(\sqrt{3}-\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}=\frac{4(\sqrt{3}-\sqrt{2})}{3-2}=4\sqrt{3}-4\sqrt{2}\)
Answer: \(4\sqrt{3}-4\sqrt{2}\)
Solution: Multiply by \(\sqrt{3}-\sqrt{2}\): \(\frac{4(\sqrt{3}-\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}=\frac{4(\sqrt{3}-\sqrt{2})}{3-2}=4\sqrt{3}-4\sqrt{2}\)
Answer: \(4\sqrt{3}-4\sqrt{2}\)
4. Problem-Solving Techniques
- Identify Denominator Type: Check if it’s a single radical (choose \(\sqrt[n]{k^{n-1}}\)) or binomial radical (use conjugate).
- Multiply Consistently: Always multiply both numerator and denominator by the same factor to preserve value.
- Simplify After Rationalizing: Reduce coefficients or simplify remaining radicals (e.g., \(\sqrt{8}=2\sqrt{2}\)).
- Check Sign & Index: For even indices, ensure radicands ≥ 0; for odd indices, avoid denominator radicand = 0.