1. Fundamental Concepts
- Definition: An absolute value equation is an equation that contains an absolute value expression.
- Absolute Value: The absolute value of a number is its distance from zero on the number line, always non-negative.
- Solving Strategy: To solve an absolute value equation, isolate the absolute value expression and set up two separate equations: one with the positive value and one with the negative value.
2. Key Concepts
Basic Rule: $$|x| = a \implies x = a \text{ or } x = -a$$
Degree Preservation: The solution to an absolute value equation can have at most two solutions.
Application: Used in various real-world scenarios such as physics, engineering, and economics for modeling distances and tolerances.
3. Examples
Example 1 (Basic)
Problem: Solve $$|2x + 3| = 7$$
Step-by-Step Solution:
- Set up two equations: $$2x + 3 = 7 \text{ and } 2x + 3 = -7$$
- Solve each equation:
- For $$2x + 3 = 7$$: Subtract 3 from both sides to get $$2x = 4$$. Divide by 2 to get $$x = 2$$.
- For $$2x + 3 = -7$$: Subtract 3 from both sides to get $$2x = -10$$. Divide by 2 to get $$x = -5$$.
Validation: Substitute $$x = 2$$ and $$x = -5$$ into the original equation to verify.
Example 2 (Intermediate)
Problem: Solve $$|3x - 4| + 2 = 8$$
Step-by-Step Solution:
- Isolate the absolute value expression: Subtract 2 from both sides to get $$|3x - 4| = 6$$.
- Set up two equations: $$3x - 4 = 6 \text{ and } 3x - 4 = -6$$
- Solve each equation:
- For $$3x - 4 = 6$$: Add 4 to both sides to get $$3x = 10$$. Divide by 3 to get $$x = \frac{10}{3}$$.
- For $$3x - 4 = -6$$: Add 4 to both sides to get $$3x = -2$$. Divide by 3 to get $$x = -\frac{2}{3}$$.
Validation: Substitute $$x = \frac{10}{3}$$ and $$x = -\frac{2}{3}$$ into the original equation to verify.
4. Problem-Solving Techniques
- Isolation Technique: Always start by isolating the absolute value expression on one side of the equation.
- Case Analysis: After isolation, consider both the positive and negative cases separately.
- Verification Step: Always check your solutions by substituting them back into the original equation.