1. Fundamental Concepts
- Definition: Rational equations are equations involving fractions with variables in the denominator.
- Common Denominator: The process of finding a common denominator to solve rational equations.
- Extraneous Solutions: Solutions that do not satisfy the original equation due to domain restrictions.
2. Key Concepts
Basic Rule: $$\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}$$
Degree Preservation: The highest degree in the result matches input
Application: Used to solve real-world problems involving rates and proportions
3. Examples
Example 1 (Basic)
Problem: Solve the equation $$\frac{x}{x-2} + \frac{3}{x+2} = 4$$
Step-by-Step Solution:
- Find a common denominator: $$(x-2)(x+2)$$
- Multiply each term by the common denominator: $$x(x+2) + 3(x-2) = 4(x^2 - 4)$$
- Simplify and solve for \(x\): $$x^2 + 2x + 3x - 6 = 4x^2 - 16$$
- Rearrange terms: $$0 = 3x^2 - 5x - 10$$
- Solve using the quadratic formula: $$x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(3)(-10)}}{2(3)}$$
Validation: Substitute \(x = \text{{values}}\) into the original equation to check.
Example 2 (Intermediate)
Problem: A river flows at a speed of 4 miles per hour. A boat travels 12 miles upstream and then returns downstream in a total time of 3.5 hours. Find the speed of the boat in still water.
Step-by-Step Solution:
- Let \(v\) be the speed of the boat in still water. The speed upstream is \(v-4\) and downstream is \(v+4\).
- The time taken upstream is \(\frac{12}{v-4}\) and downstream is \(\frac{12}{v+4}\).
- Total time equation: $$\frac{12}{v-4} + \frac{12}{v+4} = 3.5$$
- Solve for \(v\): $$\frac{12(v+4) + 12(v-4)}{(v-4)(v+4)} = 3.5$$
- Simplify and solve: $$24v = 3.5(v^2 - 16)$$
Validation: Substitute \(v = \text{{values}}\) into the original equation to check.
4. Problem-Solving Techniques
- Visual Strategy: Draw diagrams to represent the problem visually.
- Error-Proofing: Always check solutions in the original equation to avoid extraneous solutions.
- Concept Reinforcement: Practice with a variety of problems to reinforce understanding.